document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=967719>Question 967719</A>: <I><SPAN STYLE=\"word-break: break-all;\"> \r<BR>\n" );
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document.write( "One number is 7 times a first number. A third number is 100 more than the first. If the sum of the three numbers is 793, find the numbers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #591536 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=591536\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> X IS THE FIRST NUMBER<BR>\n" );
document.write( "7X IS THE SECOND NUMBER<BR>\n" );
document.write( "X=X+100 IS THE THIRD NUMBER<BR>\n" );
document.write( "X+7X+X+100=793<BR>\n" );
document.write( "9X=793-100<BR>\n" );
document.write( "9X=693<BR>\n" );
document.write( "X=693/9<BR>\n" );
document.write( "X=77 ANS<BR>\n" );
document.write( "7*77=539 ANS.<BR>\n" );
document.write( "77+100=177 ANS.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "77+539+177=793<BR>\n" );
document.write( "793=793 </SPAN>\n" );
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