document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=967752>Question 967752</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is 3cm longer than the width. If the length is increased by 2 cm but the width remains unchanged a new rectangle is created. The area of the new rectangle is 10 cm^2 larger that the area of the original rectangle. Find the width of the original rectangle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #591481 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39617)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=591481\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> w width<BR>\n" );
document.write( "L length<BR>\n" );
document.write( "L=w+3\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "IF:<BR>\n" );
document.write( "w*(w+3+2)-w(w+3)=10<BR>\n" );
document.write( "THEN:<BR>\n" );
document.write( "solve for w. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );