document.write( "Question 967716: How long will it take to earn your first million dollars if you annually invest $1000 into an IRA at 10% interest compounded monthly.
\n" ); document.write( "This answer should be calculated using logarithms so that the answer is exact.
\n" ); document.write( "

Algebra.Com's Answer #591478 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
\r
\n" ); document.write( "\n" ); document.write( "To calculate this value exactly, a fairly simple formula can be utilized.\r
\n" ); document.write( "\n" ); document.write( "\"A=P%281%2B%28r%2Fn%29%29%5E%28n%2At%29\"\r
\n" ); document.write( "\n" ); document.write( "\"P\"=principal (\"1000\")
\n" ); document.write( "\"r\"=annual nominal interest rate (\".10\")
\n" ); document.write( "\"n\"=number of compounding during year (\"12\", because of \"12\" months)
\n" ); document.write( "\"t\"=number of years (unknown)
\n" ); document.write( "\"A\"=amount after \"t\" years (first \"1000000\")\r
\n" ); document.write( "\n" ); document.write( "This formula yields results when we have the time known, but in this case we need to isolate \"\"t\"\" for the time necessary for the principal to turn into $\"1000000\". So we need to rearrange the formula into a fairly complex logarithmic formula:\r
\n" ); document.write( "\n" ); document.write( "\"log%28A%29=log%28P%281%2B%28r%2Fn%29%29%5E%28n%2At%29%29\"\r
\n" ); document.write( "\n" ); document.write( "\"log%28A%29=log%28P%29%2Blog%28%281%2B%28r%2Fn%29%29%5E%28n%2At%29%29%29\"\r
\n" ); document.write( "\n" ); document.write( "\"log%28A%29-log%28P%29=log%28%281%2B%28r%2Fn%29%29%5E%28n%2At%29%29%29\"\r
\n" ); document.write( "\n" ); document.write( "\"log%28A%2FP%29=%28n%2At%29log%28%281%2B%28r%2Fn%29%29%29\"\r
\n" ); document.write( "\n" ); document.write( "\"log%28A%2FP%29%2Flog%28%281%2B%28r%2Fn%29%29%29=%28n%2At%29\"\r
\n" ); document.write( "\n" ); document.write( "\"t=log%28A%2FP%29%2F%28%28n%2Alog%281%2B%28r%2Fn%29%29%29%29\"\r
\n" ); document.write( "\n" ); document.write( "Then substitute the numbers into the equation -\r
\n" ); document.write( "\n" ); document.write( "\"t=log%281000000%2F1000%29%2F%28%2812%2Alog%281%2B%280.10%2F12%29%29%29%29\"\r
\n" ); document.write( "\n" ); document.write( "\"t=log%281000%29%2F%2812%2Alog%281.008333333333333%29%29\"\r
\n" ); document.write( "\n" ); document.write( "\"t=69.36\"\r
\n" ); document.write( "\n" ); document.write( "Finally we got the answer - it'll take about \"69\" years and a four months!!! \r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );