document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=967699>Question 967699</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find an equation for the parabola shown in the figure.\r<BR>\n" );
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document.write( "http://www.webassign.net/waplots/a/6/5c377b7c207453d352fef3f6587777.gif\r<BR>\n" );
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document.write( "(if a hyper link isn't attached then copy and paste to see the figure)I did add what the figure is showing below.<BR>\n" );
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document.write( "Vertex:(-2,3)<BR>\n" );
document.write( "with a point at (2,2)\r<BR>\n" );
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document.write( "So, what I knew about this question was that the basic equation for a parabola is  (x-h)^2 = 4p(y-k)\r<BR>\n" );
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document.write( "which I substituted (-2,3) for (h,k)\r<BR>\n" );
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document.write( "(x+2)^2 = 4p(y-3)\r<BR>\n" );
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document.write( "But I'm stuck as to where the point(2,2) would go into that equation. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #591476 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39620)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=591476\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The point (2,2) is a point on the parabola.  \r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%282%2B2%29%5E2=4p%282-3%29 ALIGN=MIDDLE  ALT=\"%282%2B2%29%5E2=4p%282-3%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >, which means you can solve for the factor, p. </SPAN>\n" );
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