document.write( "Question 967652: find the angle from the line x+2y-3=0 to the line 2x-3y+8=0. \n" ); document.write( "
Algebra.Com's Answer #591428 by Alan3354(69443)\"\" \"About 
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find the angle from the line x+2y-3=0 to the line 2x-3y+8=0.
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\n" ); document.write( "Find the slope of each line.
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\n" ); document.write( "x+2y-3=0 --> y = (-1/2)x + b --> m1 = -1/2
\n" ); document.write( "2x-3y+8=0 --> y = (2/3)x + b --> m2 = 2/3
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\n" ); document.write( "The slope is the tangent of the angle wrt the x-axis.
\n" ); document.write( "Angle 1 = atan(-1/2) = -26.565 degs
\n" ); document.write( "Angle 2 = atan(2/3) = 33.69 degs
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\n" ); document.write( "The small angle at the intersection is the difference.
\n" ); document.write( "= 60.255 degs
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\n" ); document.write( "The large angle = 180 - 60.255 = 119.745 degs
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