document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=967449>Question 967449</A>: <I><SPAN STYLE=\"word-break: break-all;\">  given that tan 0 = -1/6 and 0 is in the fourth quadrant m, determine cos 0 round your answer to three decimal places </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #591392 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=591392\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> given that tan 0 = -1/6 and 0 is in the fourth quadrant m, determine cos 0 round your answer to three decimal places<BR>\n" );
document.write( "***<BR>\n" );
document.write( "hypotenuse of reference right triangle in quadrant IV =&#8730;(6^2+1^2)=&#8730;37<BR>\n" );
document.write( "cos 0=6/&#8730;37=(6&#8730;37)/37&#8776;0.986 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );