document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=967587>Question 967587</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If I know that sin=-3/sqrt(10) and cos=-1/sqrt(10) how do I find tan(2theta+3pi/2)?\r<BR>\n" );
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document.write( "Thank you </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #591369 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=591369\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If I know that sin=-3/sqrt(10) and cos=-1/sqrt(10) how do I find tan(2theta+3pi/2)?<BR>\n" );
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document.write( "Note:: tan(t) = sin(t)/cos(t) = [-3/sqrt(10)]/[-1/sqrt(10)] = 3<BR>\n" );
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document.write( "Your Problem::<BR>\n" );
document.write( "tan(2t+3pi/2) = -tan(2t) = -(2tan(t))/(1-tan^2(t))<BR>\n" );
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document.write( "= 6/-8 = -3/4<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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