document.write( "Question 967582: find the equation of the line which passes through the point ( -2, 1 ) and is parallel to the straight line with the equation 2x - y - 3 = 0? \n" ); document.write( "

Algebra.Com's Answer #591355 by Alan3354(69443) $\"\"$ $\"About$

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find the equation of the line which passes through the point ( -2, 1 ) and is parallel to the straight line with the equation 2x - y - 3 = 0?
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\n" ); document.write( "2x - y - 3 = 0
\n" ); document.write( "To find the slope, convert to slope-intercept form.
\n" ); document.write( "That means solve for y.
\n" ); document.write( "---
\n" ); document.write( "2x - y - 3 = 0
\n" ); document.write( "y = 2x - 3
\n" ); document.write( "The slope, m, is the coefficient of x.
\n" ); document.write( "m = 2
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\n" ); document.write( "Parallel lines have the same slope. 2, in this case.
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\n" ); document.write( "An equation, not \"the equation,\" is y - y1 = m*(x - x1)
\n" ); document.write( "(x1,y1) is (-2,1) PS don't put spaces in the points.
\n" ); document.write( "----
\n" ); document.write( "y - 1 = 2*(x + 2)
\n" ); document.write( "You can change the format.
\n" ); document.write( "y = 2x + 5
\n" ); document.write( "Same thing.
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