document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=967444>Question 967444</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If I've been given the perimeter of a rectangle which is 360 and given the length as 8x-9 how can I find my width (x) so that I have the dimensions of the rectangle.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #591299 by </B><A HREF=/tutors/aboutme.mpl?userid=amarjeeth123><B>amarjeeth123(569)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=amarjeeth123><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=591299\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Perimeter=2(length+width)<BR>\n" );
document.write( "2(8x-9+x)=360<BR>\n" );
document.write( "2(9x-9)=360<BR>\n" );
document.write( "18(x-1)=360<BR>\n" );
document.write( "x-1=20<BR>\n" );
document.write( "x=21<BR>\n" );
document.write( "The width of the rectangle is 21.<BR>\n" );
document.write( "The length of the rectangle is 159. </SPAN>\n" );
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