document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=967446>Question 967446</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A rectangular parking lot has a length that is 12 yards greater than the width. The area of the parking lot is 540 square yards. Find the length and the width. Use the formula, area=Length*width.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #591296 by </B><A HREF=/tutors/aboutme.mpl?userid=amarjeeth123><B>amarjeeth123(569)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=amarjeeth123><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=591296\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the width be x.<BR>\n" );
document.write( "Then the length is (x+12).<BR>\n" );
document.write( "Area=length*width<BR>\n" );
document.write( "x(x+12)=540<BR>\n" );
document.write( "x^2+12x-540=0<BR>\n" );
document.write( "x^2+30x-18x-540=0<BR>\n" );
document.write( "x(x+30)-18(x+30)=0<BR>\n" );
document.write( "(x-18)(x+30)=0<BR>\n" );
document.write( "x=18 is the only positive solution.<BR>\n" );
document.write( "The width is 18 yards.<BR>\n" );
document.write( "The length is 30 yards. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );