document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=967448>Question 967448</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The floor of a shed has an area of 88 square feet. The floor is in the shape of a rectangle whose length is 5 feet less than twice the width. Find the length and the width of the floor of the shed. Use the formula, area=length*width. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #591293 by </B><A HREF=/tutors/aboutme.mpl?userid=amarjeeth123><B>amarjeeth123(569)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=amarjeeth123><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=591293\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the width be x.<BR>\n" );
document.write( "Then the length is (2x-5).<BR>\n" );
document.write( "area=length*width<BR>\n" );
document.write( "x(2x-5)=88<BR>\n" );
document.write( "2x^2-5x-88=0<BR>\n" );
document.write( "2x^2-16x+11x-88=0<BR>\n" );
document.write( "2x(x-8)+11(x-8)=0<BR>\n" );
document.write( "(2x+11)(x-8)=0<BR>\n" );
document.write( "x=8 is the only positive solution.<BR>\n" );
document.write( "The width of the shed is 8 feet.<BR>\n" );
document.write( "The length of the shed is 11 feet. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );