document.write( "Question 967395: A car travels 120 miles. A second car traveling 10 mph faster than the first car.makes the same trip in 1 hr less time. Find speed of each car. \n" ); document.write( "
Algebra.Com's Answer #591279 by MathTherapy(10555)\"\" \"About 
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\n" ); document.write( "A car travels 120 miles. A second car traveling 10 mph faster than the first car.makes the same trip in 1 hr less time. Find speed of each car.
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Let speed of slower car be S
\n" ); document.write( "Then speed of faster car is: S + 10
\n" ); document.write( "We then get: \"120%2FS+=+120%2F%28S+%2B+10%29+%2B+1\"
\n" ); document.write( "\"120%28S+%2B+10%29+=+120S+%2B+S%28S+%2B+10%29\" ------- Multiplying by LCD, S(S + 10)
\n" ); document.write( "\"120S+%2B+1200+=+120S+%2B+S%5E2+%2B+10S\"
\n" ); document.write( "\"S%5E2+%2B+120S+%2B+10S+-+120S+-+1200+=+0\"
\n" ); document.write( "\"S%5E2+%2B+10S+-+1200+=+0\"
\n" ); document.write( "(S - 30)(S + 40) = 0
\n" ); document.write( "S, or speed of slower car = \"highlight_green%2830%29\" mph OR S = - 40 (ignore)
\n" ); document.write( "Speed of faster car: 30 + 10, or \"highlight_green%2840%29\" mph \n" ); document.write( "
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