document.write( "Question 967300: A rectangle is 5 cm longer than it is wide. If the length and breadth are increased by 2 cm each, the area increases by 50 cm^2. Find the dimension of the original rectangle. \n" ); document.write( "
Algebra.Com's Answer #591198 by josgarithmetic(39617)\"\" \"About 
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Your description implies that width and breadth are the same direction.\r
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\n" ); document.write( "\n" ); document.write( "x, length
\n" ); document.write( "y, breadth or width\r
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\n" ); document.write( "\n" ); document.write( "x=y+5;\r
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\n" ); document.write( "\n" ); document.write( "\"xy=A\";
\n" ); document.write( "\"%28x%2B2%29%28y%2B2%29-xy=50\"
\n" ); document.write( "\"xy%2B2x%2B2y-4-xy=50\"
\n" ); document.write( "\"2x%2B2y-4=50\"
\n" ); document.write( "substitute now for x from the described relation with y.
\n" ); document.write( "\"2%28y%2B5%29%2B2y-4=50\"
\n" ); document.write( "...\r
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\n" ); document.write( "\n" ); document.write( "Should be clear enough, no expected difficulty to finish.
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