document.write( "Question 966858: A container has a length four times its height,which is half of its width.If its volume is 1000 cubic meters, what is the length of the container ? \n" ); document.write( "

Algebra.Com's Answer #591158 by KMST(5328) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"H\"$ = height of the container, in meters.
\n" ); document.write( " $\"L\"$ = length of the container, in meters.
\n" ); document.write( " $\"W\"$ = width of the container, in meters.
\n" ); document.write( "\"A container has a length four times its height\" means $\"L=4H\"$ .
\n" ); document.write( "The fact that the height of the containers \"is half of its width\" means that
\n" ); document.write( " $\"H=W%2F2\"$ <--> $\"2H=W\"$
\n" ); document.write( "The container seems to be box-shaped (a right rectangular prism),
\n" ); document.write( "so its volume would be calculated by multiplying its three dimensions:
\n" ); document.write( " $\"Volume=L%2AW%2AH\"$ , so $\"L%2AW%2AH=1000\"$ .
\n" ); document.write( "substituting $\"W=2H\"$ and $\"L=4H\"$ , we get
\n" ); document.write( " $\"%284H%29%2A%282H%29%2AH=1000\"$ --> $\"8H%5E3=1000\"$ --> $\"H%5E3=1000%2F8\"$ --> $\"H%5E3=125\"$ --> $\"H=root%283%2C125%29\"$ --> $\"H=5\"$ .
\n" ); document.write( "So $\"system%28H=5%2CL=4H%29\"$ ---> $\"L=4%2A5\"$ ---> $\"highlight%28L=20%29\"$ \n" ); document.write( "

\n" );