document.write( "Question 967016: I have an average of 101 in my class that is worth 80% of my grade. What do I need to get on the final which is worth 20%, to have a 94% average at the end of the term? \n" ); document.write( "

Algebra.Com's Answer #591152 by KMST(5328) $\"\"$ $\"About$

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$\"%2280%25%22=80%2F100=0.8\"$ and $\"%2220%25%22=20%2F100=0.2\"$
\n" ); document.write( "If the grade for the final is $\"x\"$ ,
\n" ); document.write( "that would give you an average grade of
\n" ); document.write( " $\"0.8%2A101%2B0.2x=80.8%2B0.2x\"$
\n" ); document.write( "For an an average grade of $\"94\"$ you need $\"x\"$ to be the solution to
\n" ); document.write( " $\"80.8%2B0.2x=94\"$
\n" ); document.write( "Solving:
\n" ); document.write( " $\"80.8%2B0.2x=94\"$
\n" ); document.write( " $\"0.2x=94-80.8\"$
\n" ); document.write( " $\"0.2x=13.2\"$
\n" ); document.write( " $\"x=13.2%2F0.2\"$
\n" ); document.write( " $\"x=66\"$
\n" ); document.write( "Of course, you may be able to count on rounding,
\n" ); document.write( "so you may have to solve
\n" ); document.write( " $\"80.8%2B0.2x=93.5\"$ , whose solution is $\"63.5\"$ ,
\n" ); document.write( "meaning that a 64 on the final would still give you an A. \n" ); document.write( "

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