document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=967168>Question 967168</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A circle has a radius of 3 feet and a central angle DEF that measures 60 degrees. What is the length of the intercepted arc DF? Use 3.14 for pi and round your answer to the nearest tenth </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #591136 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=591136\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 60 degrees/360 degrees=1/6 The length of the arc is 1/6 the length (circumference) of the circle:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1%2F6%28pi%29%28diameter%29 ALIGN=MIDDLE  ALT=\"1%2F6%28pi%29%28diameter%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >=length of arc<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%281%2F6%29%283.14%29%286+feet%29 ALIGN=MIDDLE  ALT=\"%281%2F6%29%283.14%29%286+feet%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >=length of arc<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3.14feet ALIGN=MIDDLE  ALT=\"3.14feet\"   DISABLED_style= \"max-width:90%; height:auto;\" >=length of arc Round to tenth.<BR>\n" );
document.write( "ANSWER: The length of the arc is 3.1 feet. </SPAN>\n" );
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