document.write( "Question 967164: 10 ml of 100% pure acid is added to 60 ml of 70% acid solution what percent concentration will the resulting solution have?
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Algebra.Com's Answer #591128 by ikleyn(52788)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "Notice that all concentrations in this problem are Volume-to-Volume concentrations.\r
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\n" ); document.write( "\n" ); document.write( "60 ml  of  70%-solution contains  \"70%2F100\".\"60\" = \"0.7%2A60\" = \"42\" ml  of pure acid.\r
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\n" ); document.write( "\n" ); document.write( "After adding of  10 ml  of the pure acid the total solution volume will be  70 ml,  and the total volume of the pure acid will be  42 ml + 10 ml = 52 ml.\r
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\n" ); document.write( "\n" ); document.write( "Hence,  the concentration of the obtained solution will be  \"52%2F70\" = \"0.743\" = 74.3% (approximately). \r
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\n" ); document.write( "\n" ); document.write( "Answer.  The concentration of the obtained solution will be  74.3% (approximately). \r
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