document.write( "Question 967129: A triangular-shaped wall with a base of 2x+4 & a height of x+3. The area of the triangle is 56 in.^2. What is the value of x? \n" ); document.write( "
Algebra.Com's Answer #591121 by amarjeeth123(569)\"\" \"About 
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Area=1/2*base*height
\n" ); document.write( "1/2*(2x+4)*(x+3)=56
\n" ); document.write( "(x+2)(x+3)=56
\n" ); document.write( "x^2+5x+6=56
\n" ); document.write( "x^2+5x-50=0
\n" ); document.write( "x^2+10x-5x-50=0
\n" ); document.write( "x(x+10)-5(x+10)=0
\n" ); document.write( "(x-5)(x+10)=0
\n" ); document.write( "x=5 or x=-10
\n" ); document.write( "x=5 is the only possible solution.
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