document.write( "Question 11418: HOW DO I FIND THE EQUATION OF A CIRCLE WHERE THE CENTER IS (-3, 4) AND A POINT ON THE EDGE IS (4, 6). \n" ); document.write( "
Algebra.Com's Answer #5911 by Earlsdon(6294)\"\" \"About 
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You use the standard form for the equation of a circle with center at (h, k) and radius of r.\r
\n" ); document.write( "\n" ); document.write( "\"%28x-h%29%5E2+%2B+%28y-k%29%5E2+=+r%5E2\"\r
\n" ); document.write( "\n" ); document.write( "You know where the center is: (-3, 4) so that h = -3 and k = 4 Plug these into the formula:\r
\n" ); document.write( "\n" ); document.write( "\"%28x-%28-3%29%29%5E2+%2B+%28y-4%29%5E2+=+r%5E2\"
\n" ); document.write( "\"%28x%2B3%29%5E2+%2B+%28y-4%29%5E2+=+r%5E2\" Now you need to find the radius r.\r
\n" ); document.write( "\n" ); document.write( "The radius is just the distance form the circle center to a point on the circumference. You have the location of the center (-3, 4) and the location of a point on the circumference (4, 6).\r
\n" ); document.write( "\n" ); document.write( "You can use the distance formula to find the length of the radius using these two points:\r
\n" ); document.write( "\n" ); document.write( "\"d+=+sqrt%28%28x2-x1%29%5E2+%2B+%28y2-y1%29%5E2%29\"
\n" ); document.write( "\"d+=+sqrt%28%284-%28-3%29%29%5E2+%2B+%286-4%29%29%5E2%29\"
\n" ); document.write( "\"d+=+sqrt%287%5E2+%2B+2%5E2%29\"
\n" ); document.write( "\"d+=+sqrt%2849+%2B+4%29\"
\n" ); document.write( "\"d+=+sqrt%2853%29\" This is the length of the radius r, but you really want r^2, so you will square both sides of this.\r
\n" ); document.write( "\n" ); document.write( "\"d%5E2+=+53\"\r
\n" ); document.write( "\n" ); document.write( "The equation for your circle is:\r
\n" ); document.write( "\n" ); document.write( "\"%28x%2B3%29%5E2+%2B+%28y-4%29%5E2+=+53\"
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