document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=967103>Question 967103</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Total trip to travel is d. First week he cycled 1/4 of total distance. Second week cycled 1/3 of total distance. Which expression represents distance still needed to cycle to complete the trip.  And:<BR>\n" );
document.write( "5/12d.   7/12d.   2/7d.   5/7d.  7/7d.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #591075 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=591075\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Total trip to travel is d. First week he cycled 1/4 of total distance. Second week cycled 1/3 of total distance. Which expression represents distance still needed to cycle to complete the trip. \r<BR>\n" );
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document.write( "Ans: 1 - (1/4 + 1/3) = [1-[(3+4)/12]]d = [1 - (7/12)]d = (5/12)d<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "stan H.<BR>\n" );
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document.write( " 5/12d. 7/12d. 2/7d. 5/7d. 7/7d.  </SPAN>\n" );
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