document.write( "Question 967014: Joe leaves on a car trip,driving a steady 45 mph. He expects the trip to take exactly 3 hours. After he has been driving for an hour, he realizes he has forgotten an appointment, and he needs to arrive a half hour earlier than planned. How many miles per hour will he need to drive for the rest of the trip to make his goal? \n" ); document.write( "
Algebra.Com's Answer #591046 by josmiceli(19441)\"\" \"About 
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\"+d+=+r%2At+\"
\n" ); document.write( "\"+d%5B1%5D+=+45%2A3+\"
\n" ); document.write( "\"+d%5B1%5D+=+135+\"
\n" ); document.write( "The distance he needs to drive must
\n" ); document.write( "be 135 mi
\n" ); document.write( "--------------
\n" ); document.write( "In \"+1+\" hr, he drives
\n" ); document.write( "\"+d%5B2%5D+=+45%2A1+\"
\n" ); document.write( "\"+d%5B2%5D+=+45+\" mi
\n" ); document.write( "------------------
\n" ); document.write( "The remaining distance he has to drive is:
\n" ); document.write( "\"+d%5B3%5D+=+d%5B1%5D+-+d%5B2%5D+\"
\n" ); document.write( "\"+d%5B3%5D+=+135+-+45+\"
\n" ); document.write( "\"+d%5B3%5D+=+90+\"
\n" ); document.write( "-----------------
\n" ); document.write( "He planned to drive for \"+3+-+1+=+2+\" more hrs
\n" ); document.write( "He wants to drive for \"+2+-+.5+=+1.5+\" hrs
\n" ); document.write( "\"+d%5B3%5D+=+r%2A1.5+\"
\n" ); document.write( "\"+90+=+r%2A1.5+\"
\n" ); document.write( "\"+r+=+90%2F1.5+\"
\n" ); document.write( "\"+r+=++60+\"
\n" ); document.write( "------------
\n" ); document.write( "He will need to drive \"+60+\" mi/hr to
\n" ); document.write( "arrive 1/2 hr early
\n" ); document.write( "
\n" ); document.write( "
\n" );