document.write( "Question 967038: x=2^p y=2^q xy=32 2xy^2=32 Find the value of p and the value of q. Please give explanation.Thanks in advance! \n" ); document.write( "

Algebra.Com's Answer #591026 by Fombitz(32388) $\"\"$ $\"About$

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$\"xy=2%5E%28p%2Bq%29=32\"$
\n" ); document.write( "1. $\"p%2Bq=5\"$
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\n" ); document.write( " $\"2xy%5E2=2%282%5Ep%29%282%5Eq%29%5E2=32\"$
\n" ); document.write( " $\"2%5E%28p%2B2q%29=16\"$
\n" ); document.write( "2. $\"p%2B2q=4\"$
\n" ); document.write( "Subtract eq. 1 from eq. 2,
\n" ); document.write( " $\"p%2B2q-p-q=4-5\"$
\n" ); document.write( " $\"q=-1\"$
\n" ); document.write( "Then,
\n" ); document.write( " $\"p=6\"$
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