document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=11390>Question 11390</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The problem is as follows-<BR>\n" );
document.write( "Solve by useing Substitution:<BR>\n" );
document.write( "x+y=20}<BR>\n" );
document.write( "5x+10y=200} <BR>\n" );
document.write( "I made it so the equation read y=20-x<BR>\n" );
document.write( "so then i substituted that for the equatioin 5x+10y=200. It eventualy came out to -5x=0. But just today my algebra2 teacher said that is a wrong outcome for any problem like this. Ive done it over and over but I'm still geting that answer. Can you please help me? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #5910 by </B><A HREF=/tutors/aboutme.mpl?userid=tishy><B>tishy(4)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=tishy><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=5910\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x+y=20.....equation 1<BR>\n" );
document.write( "5x+10y=200....equation 2\r<BR>\n" );
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document.write( "multiply equation 1 by negative 5\r<BR>\n" );
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document.write( "therefore you get (x) x -5, y x-5 and 20 x -5 (you must multiply everything my negative 5)\r<BR>\n" );
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document.write( "so your new equation would be -5x-5y= -100\r<BR>\n" );
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document.write( "so you work with your new equation -5x-5y= -100<BR>\n" );
document.write( "                                    5x + 10y= 200\r<BR>\n" );
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document.write( "NOTICE I made my x into a a negative 5 so that it may cross out ot contradict with the 5 in equation 2. so when i work out my problem those two will be elimianted watch closely\r<BR>\n" );
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document.write( "-5x-5y = -100<BR>\n" );
document.write( " 5x +10y = 200\r<BR>\n" );
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document.write( "therefore when i work it out the negative 5 has cancelled my 5 in equa. 2 so i am left with\r<BR>\n" );
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document.write( "-5y = -100<BR>\n" );
document.write( "+10y = 200 (so i work it ot from here on)\r<BR>\n" );
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document.write( "you ALWAYS ADD AFTER YOU HAVE DONE YOUR CANCELATION(the cancelling i did with teh 5's) so now\r<BR>\n" );
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document.write( "-5y + 10y = 5\r<BR>\n" );
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document.write( "ans -100 + 200 (o i FORGOT YOU MUST ALWAYS ADD THE 2 NUMBERS AT THE END OF THE EQUATION ALSO)<BR>\n" );
document.write( " so i am left with 5 = 100 ( now what i do with this is divide) so my answer would be  100/5y = 20\r<BR>\n" );
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document.write( "so therefore in my 1st part i have discovered that y = 20\r<BR>\n" );
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document.write( " so now i have to subsitute to ensure that that is correct<BR>\n" );
document.write( "with substituion you can use any equation i will choose to use  equation 2 <BR>\n" );
document.write( " so<BR>\n" );
document.write( "5x + 10y = 200 now becomes:\r<BR>\n" );
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document.write( "5x +10(x20) = 200 (because i substitued)\r<BR>\n" );
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document.write( "5x + 200 = 200 ( so what i do next is carry the 200 on the left over to the right becasue there is a rule that states ONLY VARIABLES which are the letters can remain on the left)<BR>\n" );
document.write( " so now my problem looks like this\r<BR>\n" );
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document.write( "5x = 200 - 200 which works out to\r<BR>\n" );
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document.write( "5x = 0 <BR>\n" );
document.write( " HEY you did a Great job at trying to do it you only got mix up with your negative sign i hope this is right bye !!!!\r<BR>\n" );
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document.write( " </SPAN>\n" );
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