document.write( "Question 966872: ed rode his bike for 2 more hours than ann rode hers. ed traveled 24 miles, and ann traveled 6 miles. if they both rode at the same speed, for what length of time did ed ride his bike
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Algebra.Com's Answer #590952 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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Ed rode his bike for 2 more hours than Ann rode hers.
\n" ); document.write( " Ed traveled 24 miles, and Ann traveled 6 miles.
\n" ); document.write( "If they both rode at the same speed, for what length of time did Ed ride his bike?
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\n" ); document.write( "let t = Ed's riding time
\n" ); document.write( "Ann rode 2 hrs less, therefore
\n" ); document.write( "(t-2) = Ann's riding time
\n" ); document.write( ":
\n" ); document.write( "Write a speed equation; Speed = dist/time
\n" ); document.write( "they rode the same speed
\n" ); document.write( ":
\n" ); document.write( " $\"24%2Ft\"$ = $\"6%2F%28%28t-2%29%29\"$
\n" ); document.write( "cross multiply
\n" ); document.write( "6t = 24(t-2)
\n" ); document.write( "6t = 24t - 48
\n" ); document.write( "48 = 24t - 6t
\n" ); document.write( "48 = 18t
\n" ); document.write( "t = 48/18
\n" ); document.write( "t = 2 $\"2%2F3\"$ hrs, Ed's riding time
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\n" ); document.write( "Confirm this, find the speed of each, they should be equal.
\n" ); document.write( "Ed: 24/2.67 ~ 9 mph
\n" ); document.write( "Ann: 6/.67 ~ 9 mph; (rode two hrs less) \n" ); document.write( "

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