document.write( "Question 966938: joey visited his garden one day each week for four weeks each week his visit lasted 1 1/2 times as long as his preceding visit in the fourth week Joey spent 135 minutes in the garden how long was his visit during the first week? \n" ); document.write( "
Algebra.Com's Answer #590943 by LinnW(1048)![]() ![]() You can put this solution on YOUR website! Set t equal to the time spent of the first visit. \n" ); document.write( "1.5*t is the time for the second visit \n" ); document.write( "1.5*1.5*t is the time for the third visit \n" ); document.write( "1.5*1.5*1.5*t is the time for the fourth visit. \n" ); document.write( "t + 1.5*t + 1.5*1.5*t + 1.5*1.5*1.5*t = 135 minutes \n" ); document.write( "t + 1.5t + 2.25t + 3.375t = 135 \n" ); document.write( "(1+1.5+2.25+3.375)t = 135 \n" ); document.write( "8.125t = 135 \n" ); document.write( "divide each side by 8.125 to give us the time of the first visit \n" ); document.write( "t = 135/8.125 \n" ); document.write( "The length of the fourth visit is \n" ); document.write( "which is approximately 56.07 minutes \n" ); document.write( " \n" ); document.write( " |