document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=966923>Question 966923</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The speed of sound is approxiamately 330m/s. <BR>\n" );
document.write( "a)convert this to km/s<BR>\n" );
document.write( "b) how far away did lightning strike if it took 4s to hear the thunder? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #590931 by </B><A HREF=/tutors/aboutme.mpl?userid=BC17><B>BC17(9)</B></A><img src=\"/images/stars/stars-05.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=BC17><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=590931\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A) First how many m in a km. 1 m = 0.001 km.\r<BR>\n" );
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document.write( "Therefore 330m = 0.33km\r<BR>\n" );
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document.write( "Therefore 330m/s would = 0.33km/s\r<BR>\n" );
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document.write( "B) The common way to work out this distance of a storm is to count the time between lighting and thunder and divide by 5 the resulting answer is how many miles away the storm was.\r<BR>\n" );
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document.write( "ie lighting - 4 sec - thunder therefor 4 sec / by 5 would give you 0.8 miles! </SPAN>\n" );
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