document.write( "Question 966917: I have a similar question to one that has been answered.\r
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document.write( "The vertical displacement of the end of a robot arm (in cm) at time t (in seconds) is given by y = 8+7cos3t + 7cos6t
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document.write( "1. Find all times, t>0 (fractions of pi) where the vertical displacement is 8cm.\r
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document.write( "2. What is the first time t>0 that the vertical diplacement is 8cm?\r
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document.write( "This is what I have started doing:
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document.write( "Let x = 3t
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document.write( "y = 8 + 7cos(x) + 7cos(2x)
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document.write( "now do I divide out 7 (from cos(x) and cos(2x)) and use a trigonometric Identity cos(2x)? which gives me cos(x) + 2cos^2x-1
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document.write( "Any help in the right direction would be appreciated. Thankyou
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document.write( "Chad. \n" );
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Algebra.Com's Answer #590927 by Murthy(22)![]() ![]() ![]() You can put this solution on YOUR website! Given, y = 8+7cos3t + 7cos6t\r \n" ); document.write( "\n" ); document.write( "when y=8 cm\r \n" ); document.write( "\n" ); document.write( "8=8+7cos3t + 7cos6t\r \n" ); document.write( "\n" ); document.write( "can be rearranged as \r \n" ); document.write( "\n" ); document.write( "7(cos3t+cos6t)=0\r \n" ); document.write( "\n" ); document.write( "or cos3t+cos6t =0 \r \n" ); document.write( "\n" ); document.write( "2cos(9t/2).cos (3t/2)=0 {cosA + cosB = 2 cos(A+B/2).cos(A-B/2)}\r \n" ); document.write( "\n" ); document.write( "or cos(9t/2).cos (3t/2)=0\r \n" ); document.write( "\n" ); document.write( "This means either cos(9t/2)=0 or cos (3t/2)=0\r \n" ); document.write( "\n" ); document.write( "if cos(9t/2)=0\r \n" ); document.write( "\n" ); document.write( "9t/2= n(pi)/2\r \n" ); document.write( "\n" ); document.write( "t=n(pi)/9\r \n" ); document.write( "\n" ); document.write( "if cos (3t/2)=0\r \n" ); document.write( "\n" ); document.write( "3t/2= n(pi)/2\r \n" ); document.write( "\n" ); document.write( "t=n(pi)/3\r \n" ); document.write( "\n" ); document.write( "The first time when displacement is 8 cm is t=pi/9 \n" ); document.write( " |