document.write( "Question 966893: the length of the rectangle is 5 inches more than the width. the area is 33 square inches. find the length and width. round to the nearest tenth if necessary. \n" ); document.write( "
Algebra.Com's Answer #590915 by amarjeeth123(569)![]() ![]() ![]() You can put this solution on YOUR website! Let the width be x. \n" ); document.write( "Then the length is (x+5). \n" ); document.write( "Area=length*width \n" ); document.write( "x(x+5)=33 \n" ); document.write( "x^2+5x-33=0 \n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "x=3.764=3.8 \n" ); document.write( "The width is 3.8 units. \n" ); document.write( "The length is 8.8 units. \n" ); document.write( " |