document.write( "Question 966869: Oscar can drive 4 times as fast as Pablo can ride his bicycle. If it takes Pablo 3 hours longer than Oscar to travel 88 miles, how fast can Pablo ride his bicycle? \n" ); document.write( "
Algebra.Com's Answer #590909 by thesvw(77)\"\" \"About 
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If it took Oscar T hours to travel 88 miles, Pablo took \"T%2B3\" hours. If Pablo can ride his bike at a speed of V, Oscar can ride at a speed of 4V.\r
\n" ); document.write( "\n" ); document.write( "Lets write down equations using the above data.\r
\n" ); document.write( "\n" ); document.write( "\"+88+=+V%2A%28T%2B3%29\" (Distance=Speed*Time)\r
\n" ); document.write( "\n" ); document.write( "\"88+=+4V%2AT\"\r
\n" ); document.write( "\n" ); document.write( "multiply first equation by 4...\r
\n" ); document.write( "\n" ); document.write( "\"352+=+4VT+%2B+12V\"\r
\n" ); document.write( "\n" ); document.write( "subtract the second equation from this,\r
\n" ); document.write( "\n" ); document.write( "\"264+=+12V\"\r
\n" ); document.write( "\n" ); document.write( "\"V+=+264%2F12+=+22+\" miles per hour (The speed of Pablo)
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