document.write( "Question 966777: the ratio of william's age to harry's age is 2:5
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document.write( "five years ago the ratio was 1:3
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document.write( "in how many years time will the ratio be 4:9? \n" );
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Algebra.Com's Answer #590908 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! the ratio of william's age to harry's age is 2:5 \n" ); document.write( "five years ago the ratio was 1:3 \n" ); document.write( "in how many years time will the ratio be 4:9? \n" ); document.write( "*** \n" ); document.write( "at present: \n" ); document.write( "w=william's age \n" ); document.write( "h=harry's age \n" ); document.write( "w/h=2/5 \n" ); document.write( "w=2h/5 \n" ); document.write( "x=years ratio of w/h will be 4/9 \n" ); document.write( ".. \n" ); document.write( "5 yrs ago: \n" ); document.write( "w-5=william's age \n" ); document.write( "h-5=harry's age \n" ); document.write( "(w-5)/(h-5)=1/3 \n" ); document.write( "(2h/5-5)/(h-5)=1/3 \n" ); document.write( "h-5=3(2h/5-5) \n" ); document.write( "h-5=6h/5-15 \n" ); document.write( "h=6h/5-10 \n" ); document.write( "5h=6h-50 \n" ); document.write( "h=50 \n" ); document.write( "w=2h/5=100/5=20 \n" ); document.write( ".. \n" ); document.write( "(20+x)/(50+x)=4/9 \n" ); document.write( "4(50+x)=9(20+x) \n" ); document.write( "200+4x=180+9x \n" ); document.write( "5x=20 \n" ); document.write( "x=4 \n" ); document.write( "in how many years time will the ratio be 4:9? 4 \n" ); document.write( " \n" ); document.write( " |