document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=966697>Question 966697</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the sum of two number is 45. three times the first number plus seven times the seconds 115. find the two number </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #590881 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=590881\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> X+Y=45 MULTIPLY BY -3 & ADD.<BR>\n" );
document.write( "3X+7Y=115<BR>\n" );
document.write( "-3X-3Y=-135<BR>\n" );
document.write( "-------------<BR>\n" );
document.write( "4Y=-20<BR>\n" );
document.write( "Y=-20/4<BR>\n" );
document.write( "Y=-5 ANS<BR>\n" );
document.write( "X-5=45<BR>\n" );
document.write( "X=45+5<BR>\n" );
document.write( "X=50 ANS.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "3*50+7*-5=115<BR>\n" );
document.write( "150-35=115<BR>\n" );
document.write( "115=115 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );