document.write( "Question 966674: A says to B “My present age is five times your that age when I was an old as you are now. It the sum of their present ages is 48 years, find their present ages. \n" ); document.write( "
Algebra.Com's Answer #590830 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! let A = my present age \n" ); document.write( "let B = your present age \n" ); document.write( "then \n" ); document.write( "d = difference in the ages (A-B) \n" ); document.write( ": \n" ); document.write( "A says to B “My present age is five times your5( age when I was an old as you are now. \n" ); document.write( "A = 5(B-d) \n" ); document.write( "A = 5B - 5d \n" ); document.write( "Replace d with (A-B) \n" ); document.write( "A = 5B - 5(A-B) \n" ); document.write( "A = 5B - 5A + 5B \n" ); document.write( "A + 5A = 10B \n" ); document.write( "6A = 10B \n" ); document.write( "Simplify \n" ); document.write( "3A = 5B \n" ); document.write( "A = \n" ); document.write( ": \n" ); document.write( "If the sum of their present ages is 48 years, \n" ); document.write( "A + B = 48 \n" ); document.write( "Replace A with 5/3A \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "B = \n" ); document.write( "B = 18 yrs is B's age \n" ); document.write( "then \n" ); document.write( "48 - 18 = 30 yrs is A's age \n" ); document.write( ": \n" ); document.write( " find their present ages. A is 30; B is 18 \n" ); document.write( " |