document.write( "Question 966674: A says to B “My present age is five times your that age when I was an old as you are now. It the sum of their present ages is 48 years, find their present ages. \n" ); document.write( "
Algebra.Com's Answer #590830 by ankor@dixie-net.com(22740)\"\" \"About 
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let A = my present age
\n" ); document.write( "let B = your present age
\n" ); document.write( "then
\n" ); document.write( "d = difference in the ages (A-B)
\n" ); document.write( ":
\n" ); document.write( "A says to B “My present age is five times your5( age when I was an old as you are now.
\n" ); document.write( "A = 5(B-d)
\n" ); document.write( "A = 5B - 5d
\n" ); document.write( "Replace d with (A-B)
\n" ); document.write( "A = 5B - 5(A-B)
\n" ); document.write( "A = 5B - 5A + 5B
\n" ); document.write( "A + 5A = 10B
\n" ); document.write( "6A = 10B
\n" ); document.write( "Simplify
\n" ); document.write( "3A = 5B
\n" ); document.write( "A = \"5%2F3\"B
\n" ); document.write( ":
\n" ); document.write( "If the sum of their present ages is 48 years,
\n" ); document.write( "A + B = 48
\n" ); document.write( "Replace A with 5/3A
\n" ); document.write( "\"5%2F3\"B + B = 48
\n" ); document.write( "\"8%2F3\"B = 48
\n" ); document.write( "B = \"3%2F8\"*48
\n" ); document.write( "B = 18 yrs is B's age
\n" ); document.write( "then
\n" ); document.write( "48 - 18 = 30 yrs is A's age
\n" ); document.write( ":
\n" ); document.write( " find their present ages. A is 30; B is 18
\n" ); document.write( "
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