document.write( "Question 965502: The 1st,2nd and 3rd term of an arithmetic progression are 8-x,3x and 4x+1..find x
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Algebra.Com's Answer #590818 by Edwin McCravy(20056) $\"\"$ $\"About$

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The 1st,2nd and 3rd term of an arithmetic progression are 8-x,3x and 4x+1..find x
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document.write( "  (8-x)+d = 3x, 3x+d = 4x+1\r\n" );
document.write( "    8-x+d = 3x, -x+d = 1\r\n" );
document.write( "    -4x+d = -8     d = 1+x\r\n" );
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document.write( "     -4x+d = -8 \r\n" );
document.write( " -4x+(1+x) = -8  \r\n" );
document.write( "   -4x+1+x = -8\r\n" );
document.write( "     -3x+1 = -8\r\n" );
document.write( "       -3x = -9\r\n" );
document.write( "         x = 3\r\n" );
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document.write( "d = 1+x = 1+(3) = 4\r\n" );
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document.write( "Checking:  \r\n" );
document.write( "1st term = 8-x = 8-3 = 5\r\n" );
document.write( "2nd term = 3x = 3(3) = 9\r\n" );
document.write( "3rd term = 4x+1 = 4(3)+1 = 12+1 = 13\r\n" );
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document.write( "5,9,13 form an arithmetic sequence.\r\n" );
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document.write( "Edwin

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