document.write( "Question 966628: Find three consecutive even integers such that 5 times the sum of the first and the third is 16 greater than 9 times the second \n" ); document.write( "
Algebra.Com's Answer #590772 by ramkikk66(644)\"\" \"About 
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Find three consecutive even integers such that 5 times the sum of the first and the third is 16 greater than 9 times the second\r
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document.write( "Let the 3 integers be (n-2), n and (n+2)\r\n" );
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document.write( "Sum of 1st and 3rd = \"n+-+2+%2B+n+%2B+2+=+2%2An\"\r\n" );
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document.write( "9 times second = 9*n\r\n" );
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document.write( "So the equation is \"5+%2A+2%2An+=+9%2An+%2B+16\"\r\n" );
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document.write( "or \r\n" );
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document.write( "\"10%2An+=+9%2An+%2B+16\" i.e. \"n+=+16\"\r\n" );
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document.write( "Check: If n = 16, the 3 numbers are 14, 16 and 18.\r\n" );
document.write( "5 times sum of 14 and 18 = 32*5 = 160\r\n" );
document.write( "9 times 16 = 144\r\n" );
document.write( "160 is 16 more than 144. Correct!\r\n" );
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document.write( "Hope it's clear!\r\n" );
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