document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=966596>Question 966596</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the sum of three numbers is 60. one number is five more than a second number. it is also twice the third. find the numbers </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #590757 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=590757\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .<BR>\n" );
document.write( "F=first number=; S=second number=(1/5)F; T=third number=(1/2)F<BR>\n" );
document.write( ".  <BR>\n" );
document.write( "F+S+T=60 Substitute for S and T.<BR>\n" );
document.write( "F+(1/5)F+(1/2)F=60 Find common denominator and add.<BR>\n" );
document.write( "(10/10)F+(2/10)F+(5/10)F=60<BR>\n" );
document.write( "(17/10)F=60 Multiply each side by (10/17)<BR>\n" );
document.write( "F=600/17=35.29 ANSWER 1: The first number is 35.29.<BR>\n" );
document.write( "S=(1/5)F=7.06 ANSWER 2: The second number is 7.06.<BR>\n" );
document.write( "T=(1/2)F=17.65 ANSWER 3: The third number is 17.65.<BR>\n" );
document.write( ".<BR>\n" );
document.write( "CHECK:<BR>\n" );
document.write( "F+S+T=60<BR>\n" );
document.write( "35.29+7.06+17.65=60<BR>\n" );
document.write( "60=60  </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );