document.write( "Question 966544: find the area of a triangle with points A(-6,-10), B(4,-7), and C(-1,3) \n" ); document.write( "
Algebra.Com's Answer #590741 by Alan3354(69443)\"\" \"About 
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find the area of a triangle with points A(-6,-10), B(4,-7), and C(-1,3)
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\n" ); document.write( "Arrange the points like this:
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\n" ); document.write( "..A....B....C....A
\n" ); document.write( "-6.....4...-1...-6
\n" ); document.write( "-10...-7....3..-10
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\n" ); document.write( "Add the diagonal products starting at the upper left.
\n" ); document.write( "-6*-7 + 4*3 + -1*-10 = 42 + 12 + 10 = 64
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\n" ); document.write( "Add the diagonal products starting at the lower left.
\n" ); document.write( "-10*4 + -7*-1 + 3*-6 = -40 + 7 - 18 = -51
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\n" ); document.write( "The difference = 125
\n" ); document.write( "The area = 1/2 that, = 62.5 sq units\r
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