document.write( "Question 82480: Allied Airlines charges $90 for a ticket to fly between two cities 260 mi apart abd $150 for a ticket to fly between two cities 500 mi apart. At this rate, what would it cost for a trip between two cities 1000 mi apart? \n" ); document.write( "
Algebra.Com's Answer #59074 by stanbon(75887)\"\" \"About 
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Allied Airlines charges $90 for a ticket to fly between two cities 260 mi apart abd $150 for a ticket to fly between two cities 500 mi apart. At this rate, what would it cost for a trip between two cities 1000 mi apart?
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\n" ); document.write( "You have two points (260,90) and (500,150)
\n" ); document.write( "slope = [150-90]/[500-260] = 60/240 = 1/4
\n" ); document.write( "You want an equation of the form cost=m(distance)+b where cost is 90 when
\n" ); document.write( "distance is 260 and m=1/4; solve for \"b\":
\n" ); document.write( "90 = (1/4)260+b
\n" ); document.write( "90 = 65+b
\n" ); document.write( "b=25
\n" ); document.write( "EQUATION: Cost = (1/4)(distance)+25
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\n" ); document.write( "Cost when distance = 1000 mi:
\n" ); document.write( "cost = (1/4)(1000)=25
\n" ); document.write( "cost = 250+25
\n" ); document.write( "cost = $275
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H. \n" ); document.write( "
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