document.write( "Question 966495: Michael is 2 times as old as Christopher.
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Algebra.Com's Answer #590708 by Edwin McCravy(20060) $\"\"$ $\"About$

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Michael is 2 times as old as Christopher.
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document.write( "M = 2C\r\n" );
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\n" ); document.write( "20 years ago, Michael was 6 times as old as Christopher.
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document.write( "M-20 = 6(C-20)\r\n" );
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document.write( "System of equations\r\n" );
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document.write( "M = 2C\r\n" );
document.write( "M-20 = 6(C-20)\r\n" );
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document.write( "2C-20 = 6(C-20)\r\n" );
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document.write( "2C-20 = 6C-120\r\n" );
document.write( "  -4C = -100\r\n" );
document.write( "    C = 25\r\n" );
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document.write( "Christopher is 25\r\n" );
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\n" ); document.write( "Michael is 2 times as old as Christopher.
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document.write( "Michael is 50.\r\n" );
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document.write( "Checking: 20 years ago, Michael was 30 and Christopher was\r\n" );
document.write( "only 5, and 30 is 6 times 5.\r\n" );
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document.write( "Edwin

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