document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=82464>Question 82464</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The dimensions of a rectangle are 6cm by 8cm. When both dimensions are increased by equal amounts, the area of the rectangle is increased by 208 square cm. Find the dimensions of the new rectangle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #59069 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley75><B>checkley75(3666)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley75><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=59069\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (6+X)(8+X)=6*8+208<BR>\n" );
document.write( "48+14X+X^2=48+208<BR>\n" );
document.write( "X^2+14X-208=0<BR>\n" );
document.write( "USING THE QUADRATIC EQUATION WE GET:<BR>\n" );
document.write( "X=(-14+-SQRT[14^2-4*1*-208])/2*1<BR>\n" );
document.write( "X=(-14+-SQRT[196+832])/2<BR>\n" );
document.write( "X=(-14+-SQRT10280/2<BR>\n" );
document.write( "X=(-14+-32.06)/2<BR>\n" );
document.write( "X=(-14+32.06)/2<BR>\n" );
document.write( "X=18.06/2<BR>\n" );
document.write( "X=9.03 ANSWER.<BR>\n" );
document.write( "PROOF<BR>\n" );
document.write( "(6+9.03)(8+9.03)=48+208<BR>\n" );
document.write( "15.03*17.03=256<BR>\n" );
document.write( "256=256\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );