document.write( "Question 966341: An initial amount of a radioactive substance y0 is given, along with information about the amount remaining after a given time t in appropriate units. For an equation of the form y = y0ekt that models the situation, give the exact value of k in terms of natural logarithms: y0 = 20 mg; the half-life is 200 days. \n" ); document.write( "
Algebra.Com's Answer #590661 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! An initial amount of a radioactive substance y0 is given, along with information about the amount remaining after a given time t in appropriate units. \n" ); document.write( " For an equation of the form y = y0ekt that models the situation, give the exact value of k in terms of natural logarithms: y0 = 20 mg; the half-life is 200 days. \n" ); document.write( ": \n" ); document.write( "The equation is: \n" ); document.write( "Half remains after 200 days \n" ); document.write( " \n" ); document.write( "Y = amt after t time (10 mg) \n" ); document.write( "Yo = initial amt (20 mg) \n" ); document.write( "k = half-life of the substance \n" ); document.write( "t = time of decay (200) \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "ln of e is 1, therefore \n" ); document.write( " \n" ); document.write( "200k = -.693147 \n" ); document.write( "k = \n" ); document.write( "k = -.0034657 \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check this on your calc: 20*e^(-.0034657*200) = 10.000 \n" ); document.write( " |