document.write( "Question 966322: Information given: sin alpha=5/6, 90
Algebra.Com's Answer #590626 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! Information given: sin alpha=5/6, 90 and tan Beta=3/7, 180 what are cos(alpha+beta) sin(alpha+beta) and tan(alpha+beta) \n" ); document.write( "*** \n" ); document.write( "sin(a)=5/6 (Q2) \n" ); document.write( " \n" ); document.write( ".. \n" ); document.write( "tan(b)=3/7(Q3) \n" ); document.write( "hypotenuse of reference right triangle in quadrant III= \n" ); document.write( " \n" ); document.write( " \n" ); document.write( ".. \n" ); document.write( "cos(a+b)=cos(a)*cos(b)-sin(a)*sin(b)=(-√11/6)(-7√58/58)-(5/6)(-3√58/58)=7√638/348+15√58/348=(7√638+15√58)/348 \n" ); document.write( ".. \n" ); document.write( "sin(a+b)=sin(a)cos(b)+cos(a)sin(b)=(5/6)(-7√58/58)+(-√11/6)(-3√58/58)=-35√58/348+3√638/348=(-35√58+3√638)/348 \n" ); document.write( ".. \n" ); document.write( "tan(a+b)=sin(a+b)/cos(a+b)= (-35√58+3√638)/(7√638+15√58)/348 \n" ); document.write( ".. \n" ); document.write( "Check: \n" ); document.write( "sin(a)=5/6(Q2) \n" ); document.write( "a=123.56 \n" ); document.write( "tan(b)=3/7(Q3) \n" ); document.write( "b=203.20 \n" ); document.write( "a+b=326.76 \n" ); document.write( "cos(a+b)=cos(326.76)=0.8364 \n" ); document.write( "exact value as computed above=(7√638+15√58)/348≈0.8363 \n" ); document.write( "sin(a+b)=sin(326.76)=-0.5481 \n" ); document.write( "exact value as computed above=(-35√58+3√638)/348≈-0.5482 \n" ); document.write( " |