document.write( "Question 966312: 2 people had 270$ altogether. one person decides to give a quarter of what he has in exchange for a third of what the other person has. as a result of the exchange they both have an equal amount of money. How much did they each have at first? \n" ); document.write( "
Algebra.Com's Answer #590587 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! 2 people had 270$ altogether. one person decides to give a quarter of what he has in exchange for a third of what the other person has. as a result of the exchange they both have an equal amount of money. \n" ); document.write( " How much did they each have at first? \n" ); document.write( ": \n" ); document.write( "let a = amt one person has originally \n" ); document.write( "let b = amt the other person has \n" ); document.write( "therefore \n" ); document.write( "a + b = 270 \n" ); document.write( "a = (270-b) \n" ); document.write( ": \n" ); document.write( "\"one person decides to give a quarter of what he has in exchange for a third of what the other person has. as a result of the exchange they both have an equal amount of money.\" \n" ); document.write( "a - .25a + .33b = b - .33b + .25a \n" ); document.write( ".75a + .33b = .67b + .25a \n" ); document.write( ".75a - .25a = .67b - .33b \n" ); document.write( ".50a = .33b \n" ); document.write( "replace a with (270-b) \n" ); document.write( ".50(270-b) = .33b \n" ); document.write( "135 - .5b = .33b \n" ); document.write( "135 = .33b + .5b \n" ); document.write( "135 = .83b \n" ); document.write( "b = 135/.83 \n" ); document.write( "b = $162.65 b's amt \n" ); document.write( "then \n" ); document.write( "270 - 162.65 = $107.35 a's amt \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "See if they have the same amt \n" ); document.write( ".75(107.35) + .33(162.65) = 134.76 \n" ); document.write( "and \n" ); document.write( ".667(162.65) + (.25(107.35) = 135.33; is that close enough?\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |