document.write( "Question 965885: A group of parents are planning a children’s playground. In order to save on fencing, they are positioning the playground so that one side is immediately adjacent to the school building. If the playground is to be a rectangle 500 square yards in area, what dimensions should they use if they want to use the least amount of fencing?. \n" ); document.write( "
Algebra.Com's Answer #590531 by KMST(5328)\"\" \"About 
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\"L\"= total length of fence (in yards), \"A\"= area in square yards,
\n" ); document.write( "\"x\"= length of each side of the fence directly attached to the building
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\n" ); document.write( "If you are studying Calculus, you would want to use functions and derivatives to find the maximum of Area as a function of one of the measurements.\r
\n" ); document.write( "\n" ); document.write( "If you are not studying calculus, or learning how to use a graphing calculator, you need an easier solution:
\n" ); document.write( "The more common version of this type of problem, asks for the maximum area for a given total length of fence.
\n" ); document.write( "The general answer is that the best enclosure is always a double square,
\n" ); document.write( "meaning that the rectangular enclosure looks like two squares attached to the wall:
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\n" ); document.write( "In other words, half of the length of the fence is the long side parallel to the building wall,
\n" ); document.write( "the other half is used for the two sections of fence that connect that long side to the wall.
\n" ); document.write( "To prove that, you would write that \"A=x%28L-2x%29\"-->\"A=-2x%5E2%2BLx\" ,
\n" ); document.write( "and realize that \"A\" is a quadratic function that graphs as a parabola,
\n" ); document.write( "and has a vertex/maximum for
\n" ); document.write( "\"x=-L%2F%282%28-2%29%29\"--->\"x=L%2F4\"-->\"system%28L=4x%2CL-2x=2x%29\"
\n" ); document.write( "That gives you the most efficient way to fence three sides of an enclosure,
\n" ); document.write( "yielding the maximum area for a given total length of fence:
\n" ); document.write( "\"A%5Bmax%5D=%28L-2x%29%28x%29=%282x%29%28x%29=2x%5E2=2%28L%2F4%29%5E2=L%5E2%2F8\" or \"A%3C=L%5E2%2F8\" .
\n" ); document.write( "Obviously, \"A%5Bmax%5D\" increases with \"L\" (because \"L%3E0\" , of course).
\n" ); document.write( "So, if they just use \"40\" yards of fencing material, \"L=40\" ,
\n" ); document.write( "the largest rectangular are you can enclose is \"200\" square yards:
\n" ); document.write( "\"A%5Bmax%5D=40%5E2%2F8=1600%2F8=200\" .
\n" ); document.write( "They will need more fencing material.
\n" ); document.write( "If the parents use \"60\" yards of fencing material, \"L=60\" ,
\n" ); document.write( "the largest rectangular are you can enclose is \"450\" square yards:
\n" ); document.write( "\"A%5Bmax%5D=60%5E2%2F8=3600%2F8=450\" .
\n" ); document.write( "They will need more fencing material.
\n" ); document.write( "What total length of fencing material will they need?
\n" ); document.write( "\"A%3C=L%5E2%2F8\" ---> \"8A%3C=L%5E2\" ---> \"sqrt%288A%29%3C=L\"<--->\"L%3E=2sqrt%282A%29\" .
\n" ); document.write( "For an area of \"A=450\" square yards, they will need at least
\n" ); document.write( "\"L=2sqrt%282%2A500%29=2sqrt%281000%29=about+63.25\" yards of fencing material,
\n" ); document.write( "and the dimensions of the enclosure will be
\n" ); document.write( "\"x=L%2F4=2sqrt%281000%29%2F4=sqrt%281000%29%2F2=about\"\"highlight%2815.81%29\" yards,
\n" ); document.write( "and \"L-2x=2x=2%28sqrt%281000%29%2F2%29=sqrt%281000%29=about\"\"highlight%2831.62%29\" yards.
\n" ); document.write( "
\n" ); document.write( "IF YOU ARE STUDYING CALCULUS:
\n" ); document.write( "You would write \"A\" as a function of some measure,
\n" ); document.write( "and calculate the derivative.
\n" ); document.write( "For example, if we were to use as a variable \"x\", the length of the parallel fence sides,
\n" ); document.write( "the length of the other side would be \"500%2Fx\" ,
\n" ); document.write( "and the total length of fencing needed would be
\n" ); document.write( "\"y=2x%2B500%2Fx\"
\n" ); document.write( "The derivative of that functions is
\n" ); document.write( "\"dy%2Fdx=2-500%2Fx%5E2\"<-->\"dy%2Fdx=%282x%5E2-500%29%2Fx%5E2\" .
\n" ); document.write( "That derivative is zero when \"2x%5E2-500=0\" , for \"system%28x=sqrt%28250%29%2C%22%27or%22%2Cx=-sqrt%28250%29%29\"
\n" ); document.write( "The derivative is negative (and the function decreases) for \"-sqrt%28250%29%3Cx%3Csqrt%28250%29\" .
\n" ); document.write( "For \"x%3Esqrt%28250%29\" the derivative is positive and the function increases,
\n" ); document.write( "so the function has a maximum for \"x=sqrt%28250%29\" , which is about \"15.81\" .
\n" ); document.write( "That is the lengths of two of the sides of the fence.
\n" ); document.write( "The length of the other side of the fence is
\n" ); document.write( "\"500%2Fx=500%2Fsqrt%28250%29=2sqrt%28250%29\" , which is about \"31.62\" .
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