document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=966161>Question 966161</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The area of a rectangle is x^2 - x - 6.  The length and width are increased by 9.  Find the area of the new rectangle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #590522 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=590522\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The area of a rectangle is x^2 - x - 6.  The length and width are increased by 9.  Find the area of the new rectangle.<BR>\n" );
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document.write( "Not enough info.<BR>\n" );
document.write( "The sides of the rectangle might be x by (x^2 - x - 6)/x.<BR>\n" );
document.write( "Adding 9 --> x+9 by (x^2 + 8x - 6)/x<BR>\n" );
document.write( "--> Area = x^2 + 8x - 6 + (x+9)/x<BR>\n" );
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document.write( "The sides of the rectangle might be pi by (x^2 - x - 6)/pi.<BR>\n" );
document.write( "Adding 9 --> pi+9 by (x^2 - x - 6 + 9pi)/pi<BR>\n" );
document.write( "--> Area = x^2 - x - 6 + 9*(x^2 - x + 6)/pi<BR>\n" );
document.write( "etc </SPAN>\n" );
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