document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=82432>Question 82432</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am trying to solve this equation:<BR>\n" );
document.write( "3/x - 2/(x+1)=4/x<BR>\n" );
document.write( "I know I need to get the LCD and that would be x(x+1).<BR>\n" );
document.write( "I multiplied x+1 to the Num and dem of 3/x and I multiplied x to the num and dem of 2/(x+1). From there I get lost! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #59051 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=59051\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> good so far, but you also need to do the LCD on the 4/x ... that gives (3(x+1)/LCD)-(2x/LCD)=(4(x+1)/LCD)\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "multiplying by LCD gives 3(x+1)-2x=4(x+1) ... or 3x+3-2x=4x+4 ... -3x=1 ... x=-1/3 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );