document.write( "Question 966131: how to find the nth term of the following sequence.
\n" ); document.write( "1, -2, 3, -4, 5,...
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Algebra.Com's Answer #590504 by josgarithmetic(39618)\"\" \"About 
You can put this solution on YOUR website!
Index____________Term
\n" ); document.write( "1________________1
\n" ); document.write( "2________________1+(n-1)
\n" ); document.write( "3________________1+(n-1)
\n" ); document.write( "4________________1+(n-1)
\n" ); document.write( "That much helps understand the absolute values of the terms,
\n" ); document.write( "but the given sequence ALTERNATES in sign.\r
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\n" ); document.write( "\n" ); document.write( "Index____________Term
\n" ); document.write( "1________________\"1%2A%28-1%29%5E%28n%2B1%29\"------forces sign to be positive; n+1=1+1=2.
\n" ); document.write( "2________________1+(n-1)
\n" ); document.write( "3________________1+(n-1)
\n" ); document.write( "4________________1+(n-1)\r
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\n" ); document.write( "\n" ); document.write( "EACH term will use the same formula:
\n" ); document.write( "Index_______________Term
\n" ); document.write( "1__________________\"%281%2B%28n-1%29%29%28-1%29%5E%28n%2B1%29\"
\n" ); document.write( "2___________________\"%281%2B%28n-1%29%29%28-1%29%5E%28n%2B1%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"highlight%28%281%2B%28n-1%29%29%28-1%29%5E%28n%2B1%29%29\", still from the point of view of a simple arithmetic sequence altered to alternate in sign. This can really be made simpler:\r
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\n" ); document.write( "\n" ); document.write( "\"highlight%28highlight_green%28n%2A%28-1%29%5E%28n%2B1%29%29%29\"
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