document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=966066>Question 966066</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hello, <BR>\n" );
document.write( "I need some help with a trig equation that wants me to find the solution for tan^2x+secx = 1 (0< x< 360)(<= less than or equal to). I got 0 degrees and 360 degrees, but I don't know the other answers.Any help would be greatly appreciated.Thanks!\r<BR>\n" );
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document.write( "K. Legters </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #590485 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=590485\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> find the solution for tan^2x+secx = 1 [0< x< 360)<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=tan%5E2%28x%29%2Bsecx=1 ALIGN=MIDDLE  ALT=\"tan%5E2%28x%29%2Bsecx=1\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28sin%5E2%28x%29%2Fcos%5E2%28x%29%29%2B%281%2Fcosx%29=1 ALIGN=MIDDLE  ALT=\"%28sin%5E2%28x%29%2Fcos%5E2%28x%29%29%2B%281%2Fcosx%29=1\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "lcd: cos^2(x)<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28sin%5E2%28x%29%29%2B%28cosx%29=cos%5E2%28x%29 ALIGN=MIDDLE  ALT=\"%28sin%5E2%28x%29%29%2B%28cosx%29=cos%5E2%28x%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%281-cos%5E2%28x%29%29%2B%28cosx%29=cos%5E2%28x%29 ALIGN=MIDDLE  ALT=\"%281-cos%5E2%28x%29%29%2B%28cosx%29=cos%5E2%28x%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "2cos^2(x)-cosx-1=0<BR>\n" );
document.write( "(2cosx+1)(cosx-1)=0<BR>\n" );
document.write( "cosx=-1/2<BR>\n" );
document.write( "x=120&#730;, 240&#730;(In quadrants II and III where cos < 0<BR>\n" );
document.write( "or cosx=1<BR>\n" );
document.write( "x=0 </SPAN>\n" );
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