document.write( "Question 966041: In the morning, Maria drove to her business appointment at 70 mph. Because of higher traffic in the afternoon, her average speed on the return trip was 60 mph. This made the return trip take 1/4 hr longer. How far away was the appointment? \n" ); document.write( "
Algebra.Com's Answer #590458 by lwsshak3(11628)\"\" \"About 
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In the morning, Maria drove to her business appointment at 70 mph. Because of higher traffic in the afternoon, her average speed on the return trip was 60 mph. This made the return trip take 1/4 hr longer. How far away was the appointment?
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\n" ); document.write( "let x=distance to appointment
\n" ); document.write( "travel time=distance/speed
\n" ); document.write( "x/60-x/70=1/4
\n" ); document.write( "4x/60-4x/70=1
\n" ); document.write( "lcd:60*70=4200
\n" ); document.write( "280x-240x=4200
\n" ); document.write( "40x=4200
\n" ); document.write( "x=105
\n" ); document.write( "How far away was the appointment? 105 mi
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