document.write( "Question 966041: In the morning, Maria drove to her business appointment at 70 mph. Because of higher traffic in the afternoon, her average speed on the return trip was 60 mph. This made the return trip take 1/4 hr longer. How far away was the appointment? \n" ); document.write( "
Algebra.Com's Answer #590456 by ikleyn(52777)\"\" \"About 
You can put this solution on YOUR website!
\r
\n" ); document.write( "\n" ); document.write( "Let  \"x\"  be the distance Maria drove in one  (in each)  direction.\r
\n" ); document.write( "\n" ); document.write( "Then she spent  \"x%2F70\"  hours in the morning and  \"x%2F60\"  in the afternoon.  According to the condition,  you have an equation\r
\n" ); document.write( "\n" ); document.write( "\"x%2F60\" - \"x%2F70\" = \"1%2F4\". \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "To solve it,  multiply both sides by \"60\".\"70\" = \"4200\".  You will get\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "70*x - 60*x = \"4200%2F4\" = 1050, or \r
\n" ); document.write( "\n" ); document.write( "10*x = 1050.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Hence,  x  = 105 miles. \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Answer. The distance is  105 miles\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );