document.write( "Question 966028: The half-life of a substance is 7 hours, Using A=A0eKT, Find K \n" ); document.write( "
Algebra.Com's Answer #590437 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
This, A=A0eKT, does not mean what you want it to mean.\r
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\n" ); document.write( "\n" ); document.write( "THIS means what you want, using pure text: A=A[0]e^(KT)\r
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\n" ); document.write( "\n" ); document.write( "Inside the rendering tags, you find \"A=A%5B0%5De%5E%28KT%29\".\r
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\n" ); document.write( "\n" ); document.write( "Now to solve for K, take logarithms of the left and right sides, and then substitute appropriate values:\r
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\n" ); document.write( "\n" ); document.write( "\"ln%28A%29=ln%28A%5B0%5D%29-KT%2Aln%28e%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"ln%28A%29-ln%28A%5B0%5D%29=-KT%2A1\"\r
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\n" ); document.write( "\n" ); document.write( "\"KT=ln%28A%5B0%5D%29-ln%28A%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"K=%28ln%28A%5B0%5D%29-ln%28A%29%29%2FT\"\r
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\n" ); document.write( "\n" ); document.write( "\"highlight_green%28K=ln%28A%5B0%5D%2FA%29%2FT%29\"\r
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\n" ); document.write( "\n" ); document.write( "Then substitution,
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\n" ); document.write( "\"highlight%28K=ln%282%29%2F7%29\"
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